Easy Algebra Step-by-Step

(Marvins-Underground-K-12) #1

The Equation of a Line 191


Problem Given the slope m=

1


2


and a point (−1, 3) on the line, write the
equation of the line.

Solution
Step 1. Let (x, y) be a point on the line different from (−1, 3), then substitute
the given information into the point-slope formula: m

yy
xx

=^2


y
12 x

.


y
x


−()−


=


(^31)
2
Step 2. Solve the equation for y to get the slope-y-intercept form of the equation.
y
x



+


=


3


1


1


2


yx 3 ()x+

1


2


yx 3 +

1


2


1


2


yx 33 + =+x +

1


2


1


2


3


yx=+x

1


2


7


2


is the equation of the line.

Problem Given the slope m= −2 and a point (0, 0) on the line, write the
equation of the line.

Solution
Step 1. Let (x, y) be a point on the line different from (0, 0), then substitute
the given information into the point-slope formula: m

yy
xx

=^2


y
12 x

.


y
x



=−


0


0


2


Step 2. Solve the equation for y to get the slope-y-intercept form of the equation.
y
x



=−


0


0


2


y
x

=− 2


y = −2x is the equation of the line.
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