5 Steps to a 5 AP Calculus AB 2019 - William Ma

(Marvins-Underground-K-12) #1
MA 3972-MA-Book May 7, 2018 9:52

Limits and Continuity 87

Example 6
Find the limit: limx→ 0
3 sin 2x
2 x

.


Entery 1 =
3 sin 2x
2 x
in the calculator. You see that the graph of f(x) approaches 3 asx

approaches 0. Thus, the limx→ 0
3 sin 2x
2 x
=3. (Note that had you substitutedx=0 directly
in the original expression, you would have obtained a zero in both the numerator and
denominator.) (See Figure 6.1-1.)

[−10, 10] by [−4, 4]
Figure 6.1-1
Example 7
Find the limit: limx→ 3

1


x− 3

.


Entery 1 =

1


x− 3
into your calculator. You notice that asxapproaches 3 from the right, the
graph off(x) goes higher and higher and that asxapproaches 3 from the left, the graph of
f(x) goes lower and lower. Therefore, limx→ 3

1


x− 3
is undefined. (See Figure 6.1-2.)

[−2, 8] by [−4, 4]
Figure 6.1-2

TIP • Always indicate what the final answer is, e.g., “The maximum value of f is 5.” Use
complete sentences whenever possible.


One-Sided Limits
Let f be a function and letabe a real number. Then the right-hand limit: limx→a+f(x)
represents the limit offasxapproachesafrom the right, and the left-hand limit: limx→a−f(x)
represents the limit offasxapproachesafrom the left.

Existence of a Limit
Letfbe a function and letaandLbe real numbers. Then the two-sided limit: limx→a f(x)=L
if and only if the one-sided limits exist and limx→a+f(x)=xlim→a−f(x)=L.
Free download pdf