5 Steps to a 5 AP Calculus AB 2019 - William Ma

(Marvins-Underground-K-12) #1
MA 3972-MA-Book April 11, 2018 17:21

150 STEP 4. Review the Knowledge You Need to Score High


Note that if a point (a,f(a)) is a point of inflection, thenf′′(c)=0orf′′(c) does not
exist. (The converse of the statement is not necessarily true.)
Note there are some textbooks that define a point of inflection as a point where the
concavity changes and do not require the existence of a tangent at the point of inflection.
In that case, the point at the cusp in Figure 8.2-18 would be a point of inflection.

Example 1
The graph off′, the derivative of a functionf, is shown in Figure 8.2-19. Find the points
of inflection off and determine where the function f is concave upward and where it is
concave downward on [−3, 5].

1

1


  • 1

  • 2

  • 3


2

3

4


  • 32 – 2 – 1 0 345


y

x

f′

Figure 8.2-19

Solution:(See Figure 8.2-20.)


  • 3 035


incr. decr. incr.

concave
upward

concave
upward

] ]

concave
downward

pt. of
infl.

pt. of
infl.

+ – +

x

f′

f′′
f

Figure 8.2-20

Thus,fis concave upward on [−3, 0) and (3, 5], and is concave downward on (0, 3).
There are two points of inflection: one atx=0 and the other atx=3.
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