5 Steps to a 5 AP Calculus AB 2019 - William Ma

(Marvins-Underground-K-12) #1

MA 3972-MA-Book April 11, 2018 17:21


Graphs of Functions and Derivatives 163

Answer: fhas a change of concavity atx=0. (See Figure 8.5-4.)

f′ incr. decr.

+ –
concave
upward

concave
downward

x
f′′
f

0

Figure 8.5-4


  1. Find the values ofxwhere fhas a relative minimum. (See Figure 8.5-5.)


1

–2 0

f′(x)

x

y

Figure 8.5-5

Answer: fhas a relative minimum atx=−2. (See Figure 8.5-6.)
f′
x
f


  • 2


0

decr. incr.









Figure 8.5-6


  1. Givenf is twice differentiable, arrangef(10),f′(10),f′′(10) from smallest to
    largest. (See Figure 8.5-7.)


(^010)
y
x
f
Figure 8.5-7
Answer: f(10)=0,f′(10)>0 since fis increasing, andf′′(10)<0 since fis
concave downward. Thus, the order isf′′(10),f(10),f′(10).

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