MA 3972-MA-Book April 11, 2018 17:21
Graphs of Functions and Derivatives 163
Answer: fhas a change of concavity atx=0. (See Figure 8.5-4.)
f′ incr. decr.
+ –
concave
upward
concave
downward
x
f′′
f
0
Figure 8.5-4
- Find the values ofxwhere fhas a relative minimum. (See Figure 8.5-5.)
1
–2 0
f′(x)
x
y
Figure 8.5-5
Answer: fhas a relative minimum atx=−2. (See Figure 8.5-6.)
f′
x
f
- 2
0
decr. incr.
Figure 8.5-6
- Givenf is twice differentiable, arrangef(10),f′(10),f′′(10) from smallest to
largest. (See Figure 8.5-7.)
(^010)
y
x
f
Figure 8.5-7
Answer: f(10)=0,f′(10)>0 since fis increasing, andf′′(10)<0 since fis
concave downward. Thus, the order isf′′(10),f(10),f′(10).