5 Steps to a 5 AP Calculus AB 2019 - William Ma

MA 3972-MA-Book April 11, 2018 14:46

Applications of Derivatives 201

Step 2: Enter:y 1 =

√

((x−1)∧ 2 +x∧6).

Use the [Minimum] function of

the calculator and obtain

x=.65052 andy 1 =.44488.

Verify the result with the First

Deriative Test. Enter

y 2 =d(y1(x),x) and use the

[Zero] function and obtain

x=.65052.

0 0.65052

z′ –+ 0

z decr.

rel. min.

incr.

Thus, the shortest distance is

approximately 0.445.