MA 3972-MA-Book April 11, 2018 16:1
280 STEP 4. Review the Knowledge You Need to Score High
Area under the curve:
≈
π
4
·
1
2
[
cos(0)+2 cos
(
π/ 4
2
)
+2 cos
(
π/ 2
2
)
+2 cos
(
3 π/ 4
2
)
+cos
(
π
2
)]
≈
π
8
[
cos(0)+2 cos
(
π
8
)
+2 cos
(
π
4
)
+2 cos
(
3 π
8
)
+cos
(
π
2
)]
≈
π
8
[
1 +2(.9239)+ 2
(√
2
2
)
+2(.3827)+ 0
]
≈ 1. 9743.
TIP • When using a graphing calculator in solving a problem, you are required to write the
setup that leads to the answer. For example, if you are finding the volume of a solid, you
must write the definite integral and then use the calculator to compute the numerical
value, e.g., Volume=π
∫ 3
0 (5x)
(^2) dx= 225 π. Simply indicating the answer without
writing the integral would get you only one point for the answer. And you will not get
full credit for the problem.
13.3 Area and Definite Integrals
Main Concepts:Area Under a Curve, Area Between Two Curves
Area Under a Curve
Ify=f(x) is continuous and non-negative on [a,b], then the area under the curve of f
fromatobis:
Area=
∫b
a
f(x)dx.
Iff is continuous andf <0on[a,b], then the area under the curve fromatobis:
Area=−
∫b
a
f(x)dx.(See Figure 13.3-1.)
y
f
x
0 ab
(+)
y
x
0
ab
)–(
f
Figure 13.3-1