MA 3972-MA-Book April 11, 2018 16:5
More Applications of Definite Integrals 325
14.4 Differential Equations
Main Concepts:Exponential Growth/Decay Problems, Separable Differential
Equations
Exponential Growth/Decay Problems
- If
dy
dx
=ky, then the rate of change ofyis proportional toy. - Ifyis a differentiable function oftwithy> 0
dy
dx
=ky, theny(t)=y 0 ekt; wherey 0 is
initial value ofyandkis constant. Ifk>0, thenkis a growth constant and ifk<0,
thenkis the decay constant.
Example 1 Population Growth
If the amount of bacteria in a culture at any time increases at a rate proportional to the
amount of bacteria present and there are 500 bacteria after one day and 800 bacteria after
the third day:
(a) approximately how many bacteria are there initially, and
(b) approximately how many bacteria are there after 4 days?
Solution:
(a) Since the rate of increase is proportional to the amount of bacteria present,
then:
dy
dx
=kywhereyis the amount of bacteria at any time.
Therefore, this is an exponential growth/decay model:y(t)=y 0 ekt.
Step 1: y(1)=500 andy(3)= 800
500 =y 0 ekand 800=y 0 e^3 k
Step 2: 500=y 0 ek ⇒ y 0 =
500
ek
= 500 e−k
Substitutey 0 = 500 e−kinto 800=y 0 e^3 k.
800 =(500)
(
e−k
)(
e^3 k
)
800 = 500 e^2 k⇒
8
5
=e^2 k
Take the ln of both sides :
ln
(
8
5
)
=ln
(
e^2 k
)
ln
(
8
5
)
= 2 k
k=
1
2
ln
(
8
5
)
=ln
√
8
5