MA 3972-MA-Book April 11, 2018 16:20
396 STEP 5. Build Your Test-Taking Confidence
- The correct answer is (C).
0
1
y
x
y = 1
x = y^1 ⁄^3
Volume=π
∫ 1
0
(
y^1 /^3
) 2
dy.
Using your calculator, you obtainV= 3 π/ 5.
- The correct answer is (D).
[ [
ab^0
0
decr. incr.
rel. min.
p′ = q – +
p
The graph in choice (D) is the one that satisfies
the behavior ofp.
- The correct answer is (B).
y=sinx;
dy
dx
=cosx
Set
dy
dx
=
1
2
⇒cosx=
1
2
orx=
π
3
.
Atx=
π
3
,y=sin
(
π
3
)
=
√
3
2
;
(
π
3
,
√
3
2
)
.
Equation of tangent line atx=
π
3
:
y−
√
3
2
=
1
2
(
x−
π
3
)
or
y=
1
2
(
x−
π
3
)
+
√
3
2
.
