MA 3972-MA-Book May 8, 2018 13:46
48 STEP 4. Review the Knowledge You Need to Score High
Linesl 1 andl 2 are perpendicular if and only ifm 1 m 2 =−1. (See Figure 5.1-4.)
l 1 l^2
y
0 x
Figure 5.1-4
Example 1
Write an equation of the line through the point (−1, 3) and parallel to the line 3x− 2 y=6.
(See Figure 5.1-5.)
y
0 x
3 x − 2 y = 6
(−1, 3)
− 3
Figure 5.1-5
Begin by expressing 3x− 2 y=6inslope-intercept form.
3 x− 2 y= 6
− 2 y=− 3 x+ 6
y=
− 3
− 2
x+
6
− 2
y=
3
2
x− 3
Therefore, the slope of the line 3x− 2 y=6ism=
3
2
, and the slope of the line parallel to
the line 3x− 2 y=6 is also
3
2
. Since the line parallel to 3x− 2 y=6 passes through the point
(−1, 3), you can use the point-slope form to obtain the equationy− 3 =
3
2
(x−(−1)) or
y− 3 =
3
2
(x+1).
Example 2
Write an equation of the perpendicular bisector of the line segment joining the points
A(3, 0) andB(−1, 4). (See Figure 5.1-6.)