MA 3972-MA-Book May 8, 2018 13:46
58 STEP 4. Review the Knowledge You Need to Score High
− 33 x
y
0
3
Figure 5.3-1
Since the graph ofy=
√
9 −x^2 passes the vertical line test, the equation is a function.
Lety= f(x). The expression
√
9 −x^2 implies that 9−x^2 ≥0. By inspection, note that
− 3 ≤x≤3. Thus, the domain is [−3, 3]. Sincef(x) is defined for all values ofx∈[−3, 3]
andf(−3)=0 is the minimum value and f(0)=3 is the maximum value, the range off(x)
is [0, 3].
Example 2
Givenf(x)=x^2 − 4 x, findf(−3), f(−x), and
f(x+h)−f(x)
h
.
f(−3)=(−3)^2 −4(−3)=^9 +^12 =^21
f(−x)=(−x)^2 −4(−x)=x^2 + 4 x
f(x+h)−f(x)
h
=
(x+h)^2 −4(x+h)−(x^2 − 4 x)
h
=
x^2 + 2 hx+h^2 − 4 x− 4 h−x^2 + 4 x
h
=
2 hx+h^2 − 4 h
h
= 2 x+h−4.
Operations on Functions
Let f andg be two given functions. Then for allxin the intersection of the domains of
f andg, thesum,difference,product, andquotientof f andg, respectively, are defined as
follows:
(f+g)(x)=f(x)+g(x)
(f−g)(x)=f(x)−g(x)
(fg)(x)=f(x)−g(x)
(
f
g
)
(x)=
f(x)
g(x)
,g(x)= 0
The composition offwithgis (f◦g)(x)= f(g(x)), where the domain off◦gis the set
containing allxin the domain ofgfor whichg(x) is in the domain off.
Example 1
Givenf(x)=x^2 −4 andg(x)=x−5, find
(a) (f◦g)(−1)
(b) (g◦f)(−1)
(c) (f+g)(−3)