134 STEP 4. Review the Knowledge You Need to Score High
- Iff′′(x)= 2 x−6 andf′is continuous, find the values ofxwhere fhas a point of
inflection. (See Figure 7.6-2.)
3
0–
concave
downward
concave
upward
Point of Inflection
f′′
f
x
+
Figure 7.6-2
Answer:Thus, fhas a point of inflection atx=3.
- (See Figure 7.6-3.) Find the values ofxwhere f has change of concavity.
0–2 2
5
y
x
f′(x)
Figure 7.6-3
Answer: fhas a change of concavity atx=0. (See Figure 7.6-4.)
f′ incr. decr.
+–
concave
upward
concave
downward
x
f′′
f
0
Figure 7.6-4
- (See Figure 7.6-5.) Find the values ofxwhere f has a relative minimum.
1
–2 0
f′(x)
x
y
Figure 7.6-5