148 STEP 4. Review the Knowledge You Need to Score High
(e)A possible graph is shown in
Figure 7.10-1.
(–1,0)
0
1
2
–1 1 2 3 4
possible
point of
inflection
y f
(4,2)
Figure 7.10-1
- xlim→π
2 x
sinx
→
2 π
sinπ
→
2 π
0
. Note that
L’Hoˆpital’sRule does not apply, since the
form is not
0
0
. limx→π−
2 x
sinx
=∞, but
xlim→π+
2 x
sinx
=−∞; therefore, limx→π
2 x
sinx
does
not exist.
- lim
x→^12
3 − 6 x
4 x^2 − 1
→
0
0
, but byL’Hoˆpital’sRule
lim
x→^12
3 − 6 x
4 x^2 − 1
=lim
x→^12
− 6
8 x
=
− 6
4
=
− 3
2
- To convertx^2 + 4 y^2 =4 to a polar
representation, recall thatx=rcosθand
y=rsinθ. Then, (rcosθ)^2 +4(rsinθ)^2 =4.
Simplifying givesr^2 cos^2 θ+ 4 r^2 sin^2 θ= 4
r=
2
√
cos^2 θ+4 sin^2 θ
=
2
√
1 +3 sin^2 θ