276 STEP 4. Review the Knowledge You Need to Score High
Step 2. Set up an integral.Area =∫e 3e(
1
x−(−5)
)
dx.Step 3. Evaluate the integral.Area =∫e 3e(
1
x−(−5)
)
dx=∫e 3e(
1
x+ 5
)
dx=ln|x|+ 5 x]e
3
e =[
ln(e^3 )+5(e^3 )]
−[ln(e)+5(e)]
= 3 + 5 e^3 − 1 − 5 e= 2 − 5 e+ 5 e^3.TIP • Remember: iff′>0, then f is increasing, and if f′′>0 then the graph of f is
concave upward.12.4 Volumes and Definite Integrals
Main Concepts:Solids with Known Cross Sections, The Disc Method,
The Washer MethodSolids with Known Cross Sections
IfA(x) is the area of a cross section of a solid andA(x) is continuous on [a,b], then the
volume of the solid fromx=atox=bis:V=
∫baA(x)dx.(See Figure 12.4-1.)aby0 xFigure 12.4-1Note: A cross section of a solid is perpendicular to the height of the solid.