5 Steps to a 5 AP Calculus BC 2019

(Marvins-Underground-K-12) #1
AP Calculus BC Practice Exam 1 377

x

f

y

0–1


  1. The graph offis shown above and
    f is twice differentiable. Which of the
    following has the smallest value?
    I. f(−1)
    II. f′(−1)
    III. f′′(−1)
    (A) I (B) II
    (C) III (D) II and III

  2. A particle moves in thexy-plane so that its
    velocity vector at timetis
    v(t)=



2 − 3 t^2 ,πsin(πt)


and the particle's
position vector at timet=2is


4, 3


. What is
the position vector of the particle whent=3?
(A)



−25, 0


(B)


−21, 1


(C)


−10, 0


(D)


−13, 5



  1. If
    dy
    dx
    = 3 e^2 x, and atx=0,y=


5


2


, a solution to
the differential equation is

(A) 3 e^2 x−

1


2


(B) 3 e^2 x+

1


2


(C)


3


2


e^2 x+ 1

(D)

3


2


e^2 x+ 2

40
20

–20

0 5101520

–40

t
(seconds)

v(t)

v(t)

meters/sec.


  1. The graph of the velocity function of a moving
    particle is shown above. What is the total
    displacement of the particle during
    0 ≤t≤20?
    (A) 20 m (B) 50 m
    (C) 100 m (D) 500 m

  2. Ifh′(x)=k(x) andkis a continuous function
    for all real values ofx, then


∫ 1

− 1

k(5x)dxis

(A) h(5)−h(−5)
(B) 5 h(5)− 5 h(−5)

(C)

1


5


h(5)+

1


5


h(−5)

(D)


1


5


h(5)−

1


5


h(−5)


  1. The position function of a moving particle is
    s(t)=
    t^3
    6



t^2
2
+t−3 for 0≤t≤4. What is
the maximum velocity of the particle on
the interval 0≤t≤4?

(A)

1


2


(B) 1 (C)


14


16


(D) 5



  1. Which of the following is an equation of the
    line tangent to the curve with parametric
    equationsx= 3 t^2 −2,y= 2 t^3 +2 at the point
    whent=1?
    (A) y= 3 x^2 + 7 x
    (B) y= 6 x− 2
    (C) y=x
    (D) y=x+ 3


GO ON TO THE NEXT PAGE

Free download pdf