5 Steps to a 5 AP Calculus BC 2019

(Marvins-Underground-K-12) #1

398 STEP 5. Build Your Test-Taking Confidence


Section II Part A



  1. (A) At 1:00 a.m.,t=6.
    f(6)= 96 −20 sin


(
6
4

)

= 76. 05 ◦≈ 76 ◦Fahrenheit
(B) Average temperature

=

1


12


∫ 12

0

[
96 −20 sin

(
t
4

)]
dt.
Using your calculator, you have:
Average temperature=

1


12


(992.80)


= 82. 73 ≈ 82. 7.


(C) Lety 1 = f(x)= 96 −20 sin

(
x
4

)
and
y 2 = 80.
Using the [Intersection] function of your
calculator, you obtain
x= 3. 70 ≈ 3 .7orx= 8. 85 ≈ 8. 9.
Thus, the heating system is turned on
when 3. 7 <t< 8 .9.

[−2,10] by [−10,100]

(D) Total cost
=(0.25)

∫ 8. 9

3. 7

(80−f(t))dt

=(0.25)


∫ 8. 9

3. 7

[
80 −

(
96 −20 sin

(
t
4

))]
dt

=(0.25)


∫ 8. 9

3. 7

(
− 16 +20 sin

(
t
4

))
dt.

Using your calculator, you have:

=(0.25)(13.629)= 3. 407
≈3 dollars.
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