398 STEP 5. Build Your Test-Taking Confidence
Section II Part A
- (A) At 1:00 a.m.,t=6.
f(6)= 96 −20 sin
(
6
4
)
= 76. 05 ◦≈ 76 ◦Fahrenheit
(B) Average temperature
=
1
12
∫ 12
0
[
96 −20 sin
(
t
4
)]
dt.
Using your calculator, you have:
Average temperature=
1
12
(992.80)
= 82. 73 ≈ 82. 7.
(C) Lety 1 = f(x)= 96 −20 sin
(
x
4
)
and
y 2 = 80.
Using the [Intersection] function of your
calculator, you obtain
x= 3. 70 ≈ 3 .7orx= 8. 85 ≈ 8. 9.
Thus, the heating system is turned on
when 3. 7 <t< 8 .9.
[−2,10] by [−10,100]
(D) Total cost
=(0.25)
∫ 8. 9
3. 7
(80−f(t))dt
=(0.25)
∫ 8. 9
3. 7
[
80 −
(
96 −20 sin
(
t
4
))]
dt
=(0.25)
∫ 8. 9
3. 7
(
− 16 +20 sin
(
t
4
))
dt.
Using your calculator, you have:
=(0.25)(13.629)= 3. 407
≈3 dollars.