5 Steps to a 5 AP Calculus BC 2019

(Marvins-Underground-K-12) #1

420 STEP 5. Build Your Test-Taking Confidence



  1. The correct answer is (D).
    Rewrite
    ∑∞


n= 1

3 n+^2
4 n
as

∑∞

n= 0

(3)^2


(
3 n
4 n

)
= 9

∑∞

n= 0

(
3
4

)n

= 9


(
1 +

3


4


+


(
3
4

) 2
+

(
3
4

) 3
+···

)

. Note


that 1+

3


4


+


(
3
4

) 2
+

(
3
4

) 3
is a geometric

series with a ratio of

3


4


. Thus the infinite series


is
a 1
1 −r

=


1


1 −


3


4


=4 and 9

∑∞
n= 0

(
3
4

)n
= 36.


  1. The correct answer is (D).


The limh→ 0
ln(x+h−3)−ln(x−3)
h
is the
definition of the derivative for the function
y=ln(x−3); therefore, the limit is equal to
y′=

1


x− 3

.



  1. The correct answer is (C).
    The Taylor polynomial of third degree about
    x=aisf(a)+f′(a)(x−a)+
    f′′(a)
    2!
    (x−a)^2 +
    f′′′(a)
    3!
    (x−a)^3. In this case, the third-degree
    polynomial aboutx=2is− 1 +(1)(x−2)−
    2
    2!
    (x−2)^2 +


6


3!


(x−2)^3 or− 3 +x−(x−2)^2 +
(x−2)^3.


  1. The correct answer is (A).
    Note thatf′′>0 on the intervals (−∞,−4)
    and (0, 4). Thus, the graph of the functionf is
    concave up on these intervals. Similarly,
    f′′<0 and concave down on the intervals
    (−4, 0) and (4,∞). Therefore,fhas a point of
    inflection atx=−4, 0, and 4.

  2. The correct answer is (C).


Rewrite


k
kn
as
k

(^12)
kn
or


1


kn−

12 , which is ap-series.
In order for the series to converge,

(
n−

1


2


)

must be greater than 1. Thus,n−

1


2


> 1


orn>

3


2


.



  1. The correct answer is (C).
    Sincef′(x)>0,f(x) is increasing, and since
    f′′>0,f(x) is concave up. The graph of
    f(x) may look like the one below. The right
    Riemann sum contains the largest rectangles.


y f

0 12 x
Right Riemann Sum

Right
Trapezoidal
Midpoint
Left

34
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