AP-Calculus-BC 2727-MA-Book May 11, 2018 14:10
74 STEP 4. Review the Knowledge You Need to Score High
- To find horizontal asymptotes, examine
the limx→∞f(x) and the limx→−∞f(x). The
xlim→∞f(x)=xlim→∞
x
√
x^2 + 4
. Dividing by
the highest power ofx(and in this case,
it’sx), you obtain limx→∞
x/x
√
x^2 + 4 /x
.As
x→∞,x=
√
x^2. Thus, you have
xlim→∞
x/x
√
x^2 + 4 /
√
x^2
=xlim→∞
1
√
x^2 + 4
x^2
=xlim→∞
1
√
1 +
4
x^2
=1. Thus, the liney= 1
is a horizontal asymptote.
The limx→−∞f(x)=x→lim−∞
x
√
x^2 + 4
.
Asx→−∞,x=−
√
x^2. Thus, limx→−∞
x
√
x^2 + 4
=xlim→−∞
x/x
√
x^2 + 4 /
(
−
√
x^2
)=xlim→−∞
1
−
√
1 +
4
x^2
=−1.
Therefore, the liney=−1 is a horizontal
asymptote. As for vertical asymptotes,
f(x) is continuous and defined for all real
numbers. Thus, there is no vertical
asymptote.