Barrons AP Calculus

(Marvins-Underground-K-12) #1

SOLUTION: (Quotient Rule)


Note that neither f (v) nor f ′(v) exists where the denominator equals zero,
namely, where 1 − 2v 2 = 0 or where v equals .


Example 8 __

If


SOLUTION:


Example 9 __

If y = tan ( 2x 2 + 1 ), find y′.


SOLUTION: y′ = 4 x sec^2 ( 2x 2 + 1 ).


Example 10 __

If x = cos^3 (1 − 3θ), find .


SOLUTION:


=   9   cos^2   (1  −   3θ) sin (1  −   3θ).

Example 11 __

If y = e(sin x) + 1 , find .


SOLUTION: = cos x · e(sin x) + 1.

Free download pdf