Barrons AP Calculus

(Marvins-Underground-K-12) #1

(a)


(b)


(c)


(d)


(e)


(a)


(b)


Acceleration    vector

The acceleration     vector a    is  ,   and     can     be  obtained    by  a   second

differentiation of the components of R. Thus


,

and its magnitude   is  the vector’s    length:

,

where   we  have    used    ax  and ay  for  ,  respectively.

Example 28 __

A particle moves according to the equations x = 3 cos t, y = 2 sin t.


Find    a   single  equation    in  x   and y   for the path    of  the particle    and sketch  the
curve.
Find the velocity and acceleration vectors at any time t, and show that a =
−R at all times.
Find R, v, and a when (1) , and draw them on the sketch.
Find the speed of the particle and the magnitude of its acceleration at each
instant in (c).
When is the speed a maximum? A minimum?

SOLUTIONS:


and  the     particle    moves   in  a   counterclockwise    direction   along   an  ellipse,
starting, when t = 0, at (3, 0) and returning to this point when t = 2π.
We have
R = 3 cos t, 2 sin t
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