Example 4 __
is integrated most efficiently by using formula (3) with u = 1 − 3x
and du = u′(x) dx = −3 dx.
Example 5 __
, where u = 2x^3 − 1 and du = u
′(x) dx = 6x^2 dx; this, by formula (3), equals
Example 6 __
where u = 1 − x and du
= −1 dx; this, by formula (3) yields