Barrons AP Calculus

(1)

(2)

(3)

(4)

(5)

(6)

(7)

(1)

(2)

(3)

(4)

(5)

(6)

Which graph shows the car

with    constant    acceleration?

with    the greatest    initial acceleration?

back    at  its starting    point   when    t   =   6?

that    is  farthest    from    its starting    point   at  t   =   6?

with    the greatest    average velocity?

with    the least   average velocity?

farthest    to  the left    of  its starting    point   when    t   =   6?

Figure  N6–18

SOLUTIONS:

(d),    since   acceleration    is  the derivative  of  velocity    and in  (d) v′, the slope,  is

constant.

(e),    when    t   =   0   the slope   of  this    v-curve (which  equals  acceleration)   is

greatest.

(b),    since   for this    car the net distance    traveled    (given  by  the net area)   equals

zero.

(e),    since   the area    under   the v-curve is  greatest,   this    car is  farthest    east.

(e),    the average velocity    equals  the total   distance    divided by  6,  which   is  the

net area    divided by  6   (see    (4)).

(a),    since   only    for this    car is  the net area    negative.