(D)
(E)(A)
(B)
(C)
(D)
(E)(A)
(B)(C)
(D)
(E)(A)
(B)
(C)
(D)(E)1 + e
e − 1ln 2
e
1 + e
−ln 2If we let x = tan θ, then is equivalent toIf the substitution is used, then is equivalent toThe table shows some values of continuous function f and its first
derivative. Evaluate .