Barrons AP Calculus

1.

(A)

(B)

(C)

(D)

(E)

2.

(A)

(B)

(C)

(D)

(E)

3.

(A)

(B)

(C)

(D)

(E)

4.

PRACTICE EXERCISES

Part    A.  Directions: Answer  these   questions   without using   your    calculator.

In Questions 1–10, a(t) denotes the acceleration function, v(t) the velocity
function, and s(t) the position or height function at time t. (The acceleration due
to gravity is −32 ft/sec^2 .)

If  a(t)    =   4t  −   1   and v(1)    =   3,  then    v(t)    equals

2 t^2   −   t

2 t^2   −   t   +   1

2 t^2   −   t   +   2

2 t^2   +   1

2 t^2   +   2

If  a(t)    =   20t^3   −   6t, s(−1)   =   2,  and s(1)    =   4,  then    v(t)    equals

t^5     −   t^3

5 t^4   −   3t^2    +   1

5 t^4   −   3t^2    +   3

t^5     −   t^3     +   t   +   3

t^5     −   t^3     +   1

Given   a(t),   s(−1),  and s(1)    as  in  Question    2,  then    s(0)    equals

0

1

2

3

4

A    stone   is  thrown  straight    up  from    the     top     of  a   building    with    initial

velocity     40  ft/sec  and     hits    the     ground  4   sec     later.  The     height  of  the

building,   in  feet,   is