Barrons AP Calculus

(Marvins-Underground-K-12) #1




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The slope   field   below   is  for the differential    equation
y′ = 2x
y′ = 2x − 4
y′ = 4 − 2x
y′ = y
y′ = x + y

A   solution    curve   has been    superimposed    on  the slope   field   shown   below.
The solution is for the differential equation and initial condition
y′ = tan x; y(0) = 0
y′ = cot x, y(π/4) = 1
y′ = 1 + x^2 ; y(0) = 0

y′  =   1   +   y^2 ;   y(0)    =   0
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