(A)
(B)
(C)
(D)
(E)
(A)
(B)
(C)
(D)
(E)
the differential equation satisfied by the temperature T of the corpse t hr
later is
If the corpse in Question 54 cools to 27°C in 1 hr, then its temperature (in
°C) is given by the equation
T = 22e0.205t
T = 10e1.163t
T = 10 + 22e−0.258t
T = 32e−0.169t
T = 32 − 10e−0.093t