(here R = 4 and r = sec x). Symmetry allows us to double the volume
generated by the first-quadrant portion of S. We find the upper limit of
integration by solving sec x = 4 and store the result (x = 1.31811607) as
A. Then(B) f(2) = 6 ⇒ f(2.5) = f(2) + f ′(2)(0.5) = 6 + (1.4)(0.5) = 6.7 f(2.5) = 6.7
⇒ f(3) = f(2.5) + f ′(2.5)(0.5) = 6.7 + (1.5)(0.5) = 7.45(B) . Hence .(C).(B) The power series for ln (1 − x), if (B) Solve by separation of variables; then(C) Average Rate of Change: