BC 5.
BC 6.
(b)(c)(d)1.2.3.See solution for AB/BC 5, Review Chapter 7.(a) The series is a geometric series with common ratio (x−2). The
series converges if |x−2| < 1 , so the interval of convergence is 1 < x
< 3 .
NOTE: Because this is geometric, there is no need to check
endpoints.
Geometric series with first term 2 and common ratio (x−2)..(Review Chapter 10)1 Functions
(C) f(−2) = (−2)^3 − 2(−2) − 1 = −5.(E) The denominator, x^2 + 1, is never 0.(D) Since x − 2 may not be negative, x 2. The denominator equals 0 at
x = 0 and x = 1, but these values are not in the interval x ≥ 2.