(E) Use integration by parts, letting u = arctan x and dv = dx. Then
.
The Parts Formula yields
.
(B) Hint: Note that
.
Or multiply the integrand by , recognizing that the correct answer is
equivalent to −ln |e−x − 1|.
(D) Hint: Expand the numerator and divide. Then integrate term by term.
(C) Hint: Observe that e2 ln u = u^2.
(A) Let u = 1 + ln y^2 = 1 + 2 ln |y|; integrate .
(B) Hint: Expand and note that
Use formulas (9) and (7).
(E)