(C)
Save time by finding the area under y = |x − 4| from a sketch!
(A) Since the degrees of numerator and denominator are the same, the
limit as x→∞ is the ratio of the coefficients of the terms of highest
degree: .
(D) On the interval [1, 4], f ′(x) = 0 only for x = 3. Since f (3) is a relative
minimum, check the endpoints to find that f (4) = 6 is the absolute
maximum of the function.
(C) To find lim f as x → 5 (if it exists), multiply f by .
and if x ≠ 5 this equals . So lim f (x) as x → 5 is . For f to be
continuous at x = 5, f (5) or c must also equal .
(D) Evaluate .
