.
(c) means 1 + 4 · 2−t = 1.25, so t = 4.
(d) , so the value of y approaches 10.
(a) Since . Since y = 18 − 2 · 2^2 = 10, P is at (2,10).
(b) Since . Since . Therefore
unit/sec.
(c) Let D = the object’s distance from the origin. Then
(d) The object hits the x-axis when y = 18 − 2x^2 = 0, or x = 3. Since
.
(e) The length of the arc of y = 18 − 2x^2 for 0 ≤ x ≤ 3 is given by
units.
(a) See graph.