(a)
(b)
(a)
(b)
BC ONLY
Example 17 __
Consider the polar function r = 2 + 4 sin θ.
For what values of θ in the interval [0,2π] does the curve pass through the
origin?
For what value of θ in the interval [0, π/2] does the curve intersect the circle
r = 3?
SOLUTION:
At the origin r = 0, so we want 2 + 4 sin θ = 0. Solving for θ yields sin
which occurs at and .
The curves r = 2 + 4 sin θ and r = 3 intersect when 2 + 4 sin θ = 3, or sin
. From the calculator we find .