SAT Mc Graw Hill 2011

(Marvins-Underground-K-12) #1

320 MCGRAW-HILL’S SAT


Concept Review 5




  1. To write it as a product (result of multiplication).




  2. x^2 −b^2 =(x+b)(x−b)
    x^2 + 2 xb+b^2 =(x+b)(x+b)
    x^2 − 2 xb+b^2 =(x−b)(x−b)
    x^2 +(a+b)x+ab=(x+a)(x+b)




  3. If the product of a set of numbers is 0, then at
    least one of the numbers must be 0.




  4. 108 =(2)(2)(3)(3)(3)




  5. 21mn=(3)(7)(m)(n) and 75n^2 =(3)(5)(5)(n)(n), so
    the least common multiple is
    (3)(5)(5)(7)(m)(n)(n) = 525 mn^2.




  6. 108x^6 =(2)(2)(3)(3)(3)(x)(x)(x)(x)(x)(x) and 90x^4 =
    (2)(3)(3)(5)(x)(x)(x)(x), so the greatest common
    factor is (2)(3)(x)(x)(x)(x) = 6 x^4.




  7. 1 − 49 x^4 =(1 − 7 x^2 )(1 + 7 x^2 )
    8.m^2 + 7 m+ 12 =(m+4)(m+3)




  8. 16x^2 − 40 x+ 25 =(4x−5)(4x−5) =(4x−5)^2




  9. ()yy yyy+ (^33) ()− =−+−=−^2 333 3y
    (^22)




11.


12.



  1. 4 x^2 = 12 x
    Subtract 12x: 4 x^2 − 12 x= 0
    Factor: 4 x(x−3) = 0
    Use zero product property: x=0 or 3

  2. x^2 − 8 x= 33
    Subtract 33: x^2 − 8 x− 33 = 0
    Factor: (x−11)(x+3) = 0
    Use zero product property: x=11 or − 3

  3. 3 xz− 3 yz= 60
    Factor: 3 z(x−y) = 60
    Substitute z=5: 15(x−y) = 60
    Divide by 15: (x−y) = 4


=− 912520 xx^2 +

325


3 3 3 25 3 25 2525


2
x

xx x x

()− =


()()−()()−()()+()())


xx xxx
2

1


35


1


2252


+



⎝⎜



⎠⎟


+



⎝⎜



⎠⎟


=



⎝⎜



⎠⎟



⎝⎜



⎠⎟


+



⎝⎝⎜



⎠⎟



⎝⎜



⎠⎟


+



⎝⎜



⎠⎟



⎝⎜



⎠⎟


+



⎝⎜



⎠⎟



1


2


1


35


1


3


1


2


x
⎝⎝⎜


⎠⎟


=+++


=+ +


xxx

xx

2

2

10 4 15


1


6


10


19


60


1


6


Answer Key 5: Factoring


SAT Practice 5


1.C 72 =(2)(2)(2)(3)(3) and 54 =(2)(3)(3)(3), so the
least common multiple is (2)(2)(2)(3)(3)(3) =216.
216 minutes is 3 hours 36 minutes.


2.E You can solve this one simply by plugging in
x=7 and y=1 and evaluating (7 −1)^2 −(7 +1)^2 = 36 −
64 =−28. Or you could do the algebra: (x−y)^2 −(x+y)^2
FOIL: (x^2 − 2 xy+y^2 ) −(x^2 + 2 xy+y^2 )
Simplify: − 4 xy
Substitute xy=7: −4(7) =− 28



  1. 5 (x+a)(x+1) =x^2 + 6 x+a
    FOIL: x^2 +x+ax+a=x^2 + 6 x+a
    Subtract x^2 and a: x+ax= 6 x
    Factor: x(1 +a) = 6 x
    Divide by x: 1 +a= 6
    Subtract 1: a= 5


4.A The slope is “the rise over the run,” which is
the difference of the y’s divided by the difference of
the x’s:

Or you can just choose values for mand n,like 2 and 1,
and evaluate the slope numerically. The slope between
(1, 1) and (2, 4) is 3, and the expression in (A) is the only
one that gives a value of 3.
5.A (a+b)^2 =(a+b)(a+b) =a^2 + 2 ab+b^2
Commute: =a^2 +b^2 + 2 ab
Substitute ab=− 2
and a^2 +b^2 =8: =(8) +2(−2)
= 4
6.D Factor: f^2 −g^2 =(f+g)(f−g)
Substitute f^2 −g^2 =− 10
and f+g=2: − 10 =2(f−g)
Divide by 2: − 5 =f−g

mn
mn

mnmn
mn

mn

(^22) −


=


()+ ()−


()−


=+

Free download pdf