SAT Mc Graw Hill 2011

(Marvins-Underground-K-12) #1

  1. B There are many relationships here to take
    advantage of. Notice that ∠HFGand the 76°angle
    form a “Z,” so ∠HFG= 76 °. Remember that “bi-
    sect” means to divide into two equal parts, so
    ∠HFJ=∠JFG= 38 °. Then notice that ∠JFGand
    ∠FJHform a “Z,” so ∠FJH= 38 °.

  2. A Consider the triangle with the a°angle. The
    other two angles in the triangle can be found from
    the given angles. Notice the “Z” that contains the two
    80 °angles and the “U” that contains the 130°and 50°
    angles. Therefore, a+ 80 + 50 =180, so a=50.


130 °


80 °



 1  2  3


50 °

80 °

F


H J


G


76 °


38 °

38 °

104 ° 38 °


  1. E Draw two more parallel lines and work with
    the Z’s. Your figure should look like the one above.


50 °
40 °

30 °

 1


 2


30 °

10 ° 10 °

40 °

40 °

364 McGRAW-HILL’S SAT

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