SAT Mc Graw Hill 2011

(Marvins-Underground-K-12) #1

436 McGRAW-HILL’S SAT


5. E


Simplify numerator (add exponents):

Simplify quotient
(subtract exponents):
Simplify exponent: x5/2
Rewrite as a root:


  1. C x=a^5 =b^3
    Solve for a(raise to the 1/5): x1/5=a
    Solve for b(raise to the 1/3): x1/3=b
    Multiply aand b: ab=x1/5×x1/3
    Simplify (add exponents): ab=x1/5 +1/3
    Simplify: ab=x8/15
    (Remember the quick way to add fractions:
    “zip-zap-zup” from Chapter 7, Lesson 3.)


x

5

x^42 −−(/)^12

x
x

42
− 12

xx

x

3
2

1
2
1
2

×


=



Concept Review 6



  1. 5−^2 =1/(5^2 ) =1/25



  2. 2−^5 =1/(2^5 ) =1/32




5.


6. (16/25)−3/2=1/(16/25)3/2=(25/16)3/2=((25/16)1/2)^3


7.


8.



  1. 4x−^2 =4/x^2

  2. (4y)−^2 =1/(4y)^2 =1/(16y^2 )

  3. 99 327


32 123 3
()mm mmm=⎝⎛()⎞⎠ =()=

442


12
()ggg==

xx^13 =^3

=







⎟ =



⎝⎜



⎠⎟


=


25


16


5


4


125


64


(^33)


4432 12 428


(^333)
=()=()==


25 −^12 =1 25()^12 ==1 25 1 5


99312 ==


12.



  1. x3/4=^27
    Raise both sides to the
    4/3 power: (x3/4)4/3= 27 4/3
    Simplify: x^1 =(271/3)^4
    Simplify: x= 34
    Simplify: x= 81

  2. b−1/2=^4
    Raise both sides to the
    −2 power: (b−1/2)−^2 = 4 −^2
    Simplify: b^1 =1/(4^2 )
    Simplify: b=1/16

  3. (2m)−^6 =^16
    Simplify: 2 −^6 m= 16
    Raise to the −1/2 power: 23 m= 16 −1/2
    Simplify: 23 m=
    Simplify: 23 m=1/4


116


27 9 27 9 3 3


9


(^131213121312)
1
bb b b bb
b


( ) ( ) =( ) ×( ) =×


=



(^66) = 96 b
Answer Key 6:
Negative and Fractional Exponents
SAT Practice 6



  1. 1/20 or 0.05 4 −n=1/4n=1/20

  2. B 54 ×m=^52
    Divide by 5^4 : m= 52 /5^4
    Simplify (subtract exponents): m= 5 −^2

  3. 1/4 or 0.25 2 m× 2 m× 2 m× 2 m= 2
    Simplify (add exponents): 24 m= 2
    Exponents must be equal: 4 m= 1
    Divide by 4: m=1/4


4. A


Write as powers of 3:

Simplify denominator:
Divide numerator and
denominator by 3^2 n:3^1 /1 =^3
Perhaps a simpler method is to simply pick nto be
0 (because ncan be any number). This gives
(3 × 30 )/9^0 =(3 ×1)/1 =3. The only choice that
equals 3 when n=0 is (A).

33


3


12
2

× n
n

33


3


12
2

×


()


n
n

33


9


×^2 n
n
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