Cracking The Ap Calculus ab Exam 2018

(A)4.333 (B)3.969 (C)4.344 (D)4.328 41.The side of a cube is increasing at a rate of 3 inches per second. ...

(B)y = (C)y = (D)y = 45.A particle’s height at a time t ≥ 0 is given by h(t) = 100t ...

Section II SECTION II GENERAL INSTRUCTIONS You may wish to look over the problems before starting to work o ...

On Part A, you are permitted to use your calculator to solve an equation, find the derivative of a func ...

SECTION II, PART B Time—1 hour Number of problems—4 No calculator is allowed for these problems. During the timed ...

STOP END OF EXAM ...

Practice Test 5: Answers and Explanations ...

ANSWER KEY Section I 1.A 2.C 3.D 4.C 5.D 6.C 7.B 8.B 9.C 10.C 11.A 12.A 13.C 14.B 15.B 16.D 17.A 18.B 19.B 20.D 21.C 22.C 23.B ...

35.A 36.D 37.A 38.A 39.D 40.A 41.B 42.A 43.B 44.C 45.B ...

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ANSWERS AND EXPLANATIONS TO SECTION I A First, use implicit differentiation to find : x^2 + 2xy = 0 Isolat ...

= f′(x) dx. For this problem, f (x) = V = πr^3 , f′(x) = = 4πr^2 = 100π, and dx = dr = ...

(^) ∫eu du Evaluate the integral to get eu + C Now substitute back to get e^3 x 2 C B Use u-substitution. ...

Here, if we think of f(x) as 5x^4 , then this expression gives the derivative of 5x^4 at the point ...

16. D Use u-substitution where u = 3x^3 and du = 9x^2 . Therefore, ∫ 18 x^2 sec^2 (3x^3 ) dx = 2 ∫ ...

4 (1) − 6 = 4(1)^3 + 6(1)^2 − 2 −2 = 8 = −4 C If we take the limit as x goes to ...

From the left side, we get From the right side, we get Therefore, the limit exists, and = 8. Now, l ...

either of those times, the particle is changing directions. Therefore, the distance traveled must be found ...

D Take the derivative of the x- and y-components of the position functions with respect to t: = 6 t^2 ...

A We can evaluate this integral using u-substitution. Let u = sin(2x). Then du = 2 cos(2x) dx, wh ...