Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

derivative of this curve is zero. Take the derivative.


    =   6x^2    −   6x  −   12

Set it equal to zero and solve for x. Get accustomed to doing this: It’s one of the most common questions
in differential calculus.


    =   6x^2    −   6x  −   12  =   0

6(x^2   −   x   −   2)  =   0

6(x −   2)(x    +   1)  =   0

x   =   2   or  x   =   −1

Third, find the y-coordinates of these two points.


y   =   2(8)    −   3(4)    −12(2)  +   20  =   0

y   =   2(−1)   −   3(1)    −   12(−1)  +   20  =   27

Therefore, the points are (2, 0) and (−1, 27).


PRACTICE PROBLEM SET 8


Now try these problems. The answers are in Chapter 19.


1.Find  the equation    of  the tangent to  the graph   of  y   =   3x^2    −   x   at  x   =   1.

2.Find  the equation    of  the tangent to  the graph   of  y   =   x^3     −   3x  at  x   =   3.

3.Find  the equation    of  the tangent to  the graph   of  y   =       at  x   =   3.

4.Find  the equation    of  the normal  to  the graph   of  y   =       at  x   =   4.

5.Find  the equation    of  the tangent to  the graph   of  y   =   2x^3    −   3x^2    −   12x +   20  at  x   =   2.

6.Find  the equation    of  the tangent to  the graph   of  y   =       at  x   =   5.
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