Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

or a minimum.


12(0)^2     +   12(0)   −   4   =   −4

This is negative, so the curve has a maximum at (0, 1); the curve is concave down there.


This is positive, so the curve has a minimum at ; the curve is concave up there.


12(−2)^2 + 12(−2) − 4 = 20

This is positive, so the curve has a minimum at (−2, −7) and the curve is also concave up there.


We can now plot the graph.


Finding a Cusp


If the derivative of a function approaches ∞ from one side of a point and −∞ from the other, and if the
function is continuous at that point, then the curve has a “cusp” at that point. In order to find a cusp, you
need to look at points where the first derivative is undefined, as well as where it’s zero.

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