Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

From x = −3 to x = 0, if you slice the region vertically, the curve y = is on top, and the x-axis is


on the bottom; from x = 0 to x = 3, the curve y = is on top and the x-axis is on the bottom.


Therefore, you can find the area by evaluating two integrals.


(   −   0)  dx  and  (  −   0)  dx

Your results should be


Let’s suppose you sliced the region horizontally instead. The curve y = is always on the left, and


the curve y = is always on the right. If you solve each equation for x in terms of y, you save some


time by using only one integral instead of two.


The two equations are x = y^2 − 3 and x = 3 − y^2 . We also have to change the limits of integration from x-

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