SOLUTIONS TO PRACTICE PROBLEM SET 6
- 2sin x cos x or sin 2x
Recall that = (sin x) = cosx. Here we use the Chain Rule to find the derivative: = 2(sinx)(cos x). If you recall your trigonometric identities, 2sin x cos x = sin 2x. Either answer isacceptable.- −2xsin(x^2 )
Recall that (cos x) = −sinx. Here, we use the Chain Rule to find the derivative: =(−sin(x^2 ))(2x) = −2xsin(x^2 ).- 2 sec^3 x−sec x
Recall that (tan x) = sec^2 x and that (sec x) = sec x tan x. Using the Product Rule, we get = (tan x)(sec x tan x) + (sec x)(sec^2 x). This can be simplified to sec^3 x + sec x tan^2 x = 2sec^3 x − sec x.4.
Recall that (sin x) = cos x. Here we use the Chain Rule to find the derivative: = (sin3 x) (cos 3x)(3). This can be simplified to = .5.
Recall that (sin x) = cos x. Here we use the Quotient Rule to find the derivative: = . This can be simplified to .
6. −4x csc^2 (x^2 ) cot(x^2 )
Recall that (csc x) = −csc x cot x. Here we use the Chain Rule to find the derivative: =