SOLUTIONS TO PRACTICE PROBLEM SET 6
- 2sin x cos x or sin 2x
Recall that = (sin x) = cosx. Here we use the Chain Rule to find the derivative: = 2(sin
x)(cos x). If you recall your trigonometric identities, 2sin x cos x = sin 2x. Either answer is
acceptable.
- −2xsin(x^2 )
Recall that (cos x) = −sinx. Here, we use the Chain Rule to find the derivative: =
(−sin(x^2 ))(2x) = −2xsin(x^2 ).
- 2 sec^3 x−sec x
Recall that (tan x) = sec^2 x and that (sec x) = sec x tan x. Using the Product Rule, we get
= (tan x)(sec x tan x) + (sec x)(sec^2 x). This can be simplified to sec^3 x + sec x tan^2 x = 2
sec^3 x − sec x.
4.
Recall that (sin x) = cos x. Here we use the Chain Rule to find the derivative: = (sin
3 x) (cos 3x)(3). This can be simplified to = .
5.
Recall that (sin x) = cos x. Here we use the Quotient Rule to find the derivative: =
. This can be simplified to .
6. −4x csc^2 (x^2 ) cot(x^2 )
Recall that (csc x) = −csc x cot x. Here we use the Chain Rule to find the derivative: =