Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
Next,   we  can simplify    and square  both    sides:  x^2     =   4(1 −   x^2 ).  Now,    we  can solve   this    easily. We

get x   =   ± . Next,   we  find    the y-coordinate:   y   =   ± . There   are thus    four    possible    answers

but,    if  we  look    at  the picture,    the answer  is  obviously   the point    .  We  could   verify

that    this    is  a   minimum by  taking  the second  derivative, but that    will    be  messy.  It  is  simpler to

use the calculator  to  check   the sign    of  the derivative  at  a   point   on  either  side    of  the answer, or

to  graph   the equation    for the distance.


  1. r = inches


First,  let’s   draw    a   picture.

Call    the width   of  the window  2r. Notice  that    this    is  the diameter    of  the semicircle. Call    the

height  of  the window  h.  The area    of  the rectangular portion of  the window  is  2rh,    and the

perimeter   is  2r  +   2h. The area    of  the semicircular    portion of  the window  is   ,   and     the

perimeter   is      =   πr. Therefore,  the area    of  the window  is  A   =   2rh +    ,  and the perimeter
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