Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1
4.

First,  we  take    the derivative  of  y:      =   1   +   3x^2 .  Next,   we  find    the value   of  x   where   y   =   −2: −2

=   x   +   x^3 .   You should  be  able    to  tell    by  inspection  that    x   =   −1  is  a   solution.   Or, if  you are

permitted,  use your    calculator. Remember    that    the AP  Exam    won’t   give    you a   problem where   it

is  very    difficult   to  solve   for the inverse value   of  y.  If  the algebra looks   difficult,  look    for an

obvious solution,   such    as  x   =   0   or  x   =   1   or  x   =   −1.

Now  we  can     use     the     formula     for     the     derivative  of  the     inverse     of  f(x):  

,    where  f(a)     =  c.   This    formula     means   that    we  find    the

derivative  of  the inverse of  a   function    at  a   value   a   by  taking  the reciprocal  of  the derivative  and

plugging    in  the value   of  x   that    makes   y   equal   to  a:      =   .

5. 1

First,  we  take    the derivative  of  y:      =   4   −   3x^2 .  Next,   we  find    the value   of  x   where   y   =   3:  3   =

4 x  −  x^3 .    You     should  be  able    to  tell    by  inspection  that   x    =   1   is  a   solution.   Or,     if  you     are

permitted,  use your    calculator. Remember    that    the AP  Exam    won’t   give    you a   problem where   it

is  very    difficult   to  solve   for the inverse value   of  y.  If  the algebra looks   difficult,  look    for an

obvious solution,   such    as  x   =   0   or  x   =   1   or  x   =   −1.

Now  we  can     use     the     formula     for     the     derivative  of  the     inverse     of  f(x):  

,    where  f(a)     =  c.   This    formula     means   that    we  find    the

derivative  of  the inverse of  a   function    at  a   value   a   by  taking  the reciprocal  of  the derivative  and
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