Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

  1. Maximum at (0, 0); Vertical asymptotes at x = 2 and x = −2; Horizontal asymptote at y = 3; No
    point of inflection.


First,  notice  that    the curve   goes    through the origin. There   are vertical    asymptotes  at  x   =   2   and x

=    −2.     There   is  a   horizontal  asymptote   at  y   =   3.  Next,   we  take    the     derivative:    

    =    .  Next,   we  set the derivative  equal   to  zero    to

find    any critical    points. There   is  a   solution    at  x   =   0,  which   means   that    there   is  a   critical    point   at
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