s = , so A = =
If we differentiate this with respect to t, we get = .
Now we plug in = 1.6 to get = (1.6) = 0.2P.
- C The slope of the tangent line is the derivative of the function.
Recall that ax = ax ln a. Here we get f′(x) = 3x ln 3.
Now we set the derivative equal to 1 and solve for x.
Using the calculator, we get 3x ln 3 = 1, so x ≈ −.086.
- A Use the Chain Rule to find h′(a): h′(x) = f′(g(x))(g′(x)).
We substitute a for x, and because g(a) = c, we get h′(a) = f ′(c)(g′(a)) = 6b.
- B First, we should graph the two curves.
Next, we need to find the points of intersection of the two curves, which we do by setting them
equal to each other and solving for x.
