Cracking The Ap Calculus ab Exam 2018

(Marvins-Underground-K-12) #1

ANSWERS AND EXPLANATIONS TO SECTION II


1.

Let R   be  the region  in  the first   quadrant    shown   in  the figure  above.

(a) Find    the area    of  R.

In  order   to  find    the area,   we  “slice” the region  vertically  and add up  all of  the slices. We  use
the formula for the area of the region between y = f (x) and y = g(x), from x = a to x = b,

[f(x)−g(x)] dx

We  have

f   (x) =   4   −   x^2     and g(x)    =   ex

Next,   we  need    to  find    the point   of  intersection    in  the first   quadrant.   Use your    calculator  to  find
that the point of intersection is x = 1.058 (rounded to three decimal places). Plugging into the
formula, we get

[4−x^2 −ex] dx

Evaluating  the integral,   we  get     =       =   1.957.
Free download pdf