Barrons SAT Subject Test Chemistry, 13th Edition

Rates of Chemical Reactions 9 These skills are usually tested on the SAT Subject Test in Chemistry. You should be able to... Exp ...

The nature of the reactants. In chemical reactions, some bonds break and others form. Therefore, the rates of chemical reaction ...

TIP Activation energy is the energy necessary to cause a reaction to occur. A catalyst, as explained in the preceding section, i ...

represented by aA + bB → ... the rate law expression is r ∝ [A]a[B]b or, inserting a constant of proportionality that mathematic ...

basis for predicting the effect of a concentration change of a reactant on the overall rate of reaction. Another way of determin ...

5. The addition of a catalyst to a reaction (A) changes the enthalpy (B) changes the entropy (C) changes the nature of the pro ...

Chemical Equilibrium 10 These skills are usually tested on the SAT Subject Test in Chemistry. You should be able to... Explain t ...

a static one, although in appearance the reaction seems to have stopped. An example of an equilibrium is a crystal of copper sul ...

molecular concentration of AB: where k 2 represents the rate of decomposition of AB at the fixed temperature. Both reactions can ...

forming the original reactants just as rapidly as they are being used up by the forward reaction. Therefore, no further change i ...

TIP Notice that as the forward reaction rate decreases, the reverse reaction rate increases until they are at “equilibrium.” We ...

[I 2 ] = (3.00 – x) mol/L (the same x is used since 1 mol of H 2 requires 1 mol of I 2 to react to form 2 mol of HI) [HI] = 2x m ...

At equilibrium [HI] = (2.00 − x) mol/L (For every mole of HI that decomposes, only 0.5 mole of H 2 and 0.5 mole of I 2 are forme ...

Effect of Changing the Concentrations When a system at equilibrium is disturbed by adding or removing one of the substances (thu ...

making ammonia. The reaction is N 2 (g) + 3H 2 (g) 2NH 3 (g) + heat (at equilibrium) If the concentrations of the nitrogen and h ...

concentrations of pure solids. As another example, K for the reaction NH 4 Cl(s) NH 3 (g) + HCl(g) is K = [NH 3 ][HCl] Acid Ioni ...

large value for Ka means that the concentrations of ions are relatively high. Therefore, the smaller the ionization constant of ...

Sample Problem (This sample incorporates the entire discussion of dissociation constants, including finding the pH.) Calculate ( ...

(c) The percentage of dissociation of the original acid may be expressed as Solubility Products A saturated solution of a substa ...

and Ksp = [Ba2+][SO 4 2−] Therefore Another Typical Problem Finding the solubility. If the Ksp of radium sulfate, RaSO 4 , is 4 ...