Barrons SAT Subject Test Chemistry, 13th Edition

(Marvins-Underground-K-12) #1

  1. (C) The oxidation state of oxygen in hydrogen peroxide (H 2 O 2 ) is –1. In the


products the oxidation state is both –2 (in H 2 O) and 0 (in O 2 ). Therefore, the
oxygen is being both oxidized and reduced. This process is called
disproportionation.
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