Barrons SAT Subject Test Chemistry, 13th Edition

a 0.51° increase, then

Then 14.28 g = 0.235 mol

and

Example 2

Suppose that there are two water solutions, one of glucose (molar mass = 180.),
the other of sucrose (molar mass = 342). Each contains 50.0 grams of solute in
1,000. grams (1 kg) of water. Which has the higher boiling point? The lower
freezing point?
The molality of each of these nonionizing substances is found by dividing the
number of grams of solute by the molecular mass.

Therefore, their respective molalities are 0.278 m and 0.146 m. Since the
freezing point and boiling point are colligative properties, the effect depends only
on the concentration. Because the glucose has a higher concentration, it will have
a higher boiling point and a lower freezing point. The respective boiling points
would be:

The lowering of the freezing point would be:

Although the previous discussion referenced the quantitative effects on the
boiling and freezing point of water solutions, the SAT Subject Test in Chemistry