Barrons SAT Subject Test Chemistry, 13th Edition

(Marvins-Underground-K-12) #1

  1. (C) m (mass) × ΔT (change of temperature) × specific heat = q (quantity
    of heat).


So,

10.0 g × (14° – 4° = 10°) × 4.18 J/°/g = 418 J.
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