- (C) pH + pOH = 14. In this problem, the pOH = –log [OH] = –log [10–4]
= –(–4) = 4. Placing this value in the equation, you have pH + 4 = 14.
Solving for pH, you get 10.
marvins-underground-k-12
(Marvins-Underground-K-12)
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