IMPLEMENTATION: Solve the equation:
3
4
ð 20 þxÞ¼ 1 ð 20 xÞ
41
1
3
41
ð 20 þxÞ¼
4
1
ð 20 xÞ
3 ð 20 þxÞ¼ 4 ð 20 xÞ
60 þ 3 x¼ 80 4 x
60 þ 3 xþ 4 x¼ 80 4 xþ 4 x
60 þ 7 x¼ 80
60 60 þ 7 x¼ 80 60
7 x¼ 20
71 x
7
¼
20
7
x¼ 2
6
7
miles per hour
EVALUATION: Check to see if the distance going downstream is equal to
the distance going upstream usingD¼RT.
DownstreamD¼
3
4
ð 20 þxÞ
¼
3
4
20 þ 2
6
7
¼
3
4
22
6
7
¼ 17
1
7
miles
UpstreamD¼ 1 ð 20 xÞ
¼ 120 2
6
7
¼ 17
1
7
miles
LESSON 13 Solving Distance Problems 141